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NAME
- IEEEDPSub
-
subtract one double precision IEEE number from another
SYNOPSIS
x = IEEEDPSub( y , z );
d0/d1 d0/d1 d2/d3
double x,y,z;
double x,y,z;
FUNCTION
Compute x = y - z in IEEE double precision.
INPUTS
- y
-
IEEE double precision floating point value
- z
-
IEEE double precision floating point value
RESULT
- x
-
IEEE double precision floating point value